Chapter Introduction

We begin this chapter with a reminder of a few key concepts from Chapter 5. Let f be a continuous function on [a,b] which is partitioned into n equally spaced subintervals as

a=x0<x1<⋯<xn−1<xn=b.

Let Δ⁢x=(b−a)/n denote the length of the subintervals, and let ci be any x-value in the ith subinterval. Definition 5.3.1 states that the sum

∑i=1nf⁢(ci)⁢Δ⁢x

is a Riemann Sum. Riemann Sums are often used to approximate some quantity (area, volume, work, pressure, etc.). The approximation becomes exact by taking the limit

limn→∞∑i=1nf⁢(ci)⁢Δ⁢x.

Theorem 5.3.2 connects limits of Riemann Sums to definite integrals:

limn→∞∑i=1nf⁢(ci)⁢Δ⁢x=∫abf⁢(x)⁢𝑑x.

Finally, the Fundamental Theorem of Calculus states how definite integrals can be evaluated using antiderivatives.

This chapter employs the following technique to a variety of applications. Suppose the value Q of a quantity is to be calculated. We first approximate the value of Q using a Riemann Sum, then find the exact value via a definite integral. We spell out this technique in the following Key Idea.

Key Idea 6.0.1 Application of Definite Integrals Strategy

Let a quantity be given whose value Q is to be computed.

  1. 1.

    Divide the quantity into n smaller “subquantities” of value Qi.

  2. 2.

    Identify a variable x and function f⁢(x) such that each subquantity can be approximated with the product f⁢(ci)⁢Δ⁢x, where Δ⁢x represents a small change in x. Thus Qi≈f⁢(ci)⁢Δ⁢x.

  3. 3.

    Recognize that Q≈∑i=1nQi=∑i=1nf⁢(ci)⁢Δ⁢x, which is a Riemann Sum.

  4. 4.

    Taking the appropriate limit gives Q=∫abf⁢(x)⁢𝑑x

This Key Idea will make more sense after we have had a chance to use it several times. We begin with Area Between Curves.

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