Grades 11 / 12 Tests and Answer Keys

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Student Name

  • 1.

    Three cards are chosen at random from a standard 52-card deck. What is the probability that they are not all the same color? Express your answer as a simple fraction in lowest terms.

      (2 pts) 1.

  • 2.

    Find the exact value of

    22024+2202222020+22018

    Express your answer as a simple fraction in lowest terms.

      (3 pts) 2.

  • 3.

    What is the exact value of x+y for real numbers x and y satisfying the following equation?

    x2+y2=10x6y34

      (3 pts) 3.

  • 4.

    The real numbers a, b, and c form an arithmetic sequence with abc0. The quadratic ax2+bx+c has exactly one root. What is this root?

      (3 pts) 4.

  • 5.

    In a triangle ABC, the angles satisfy the ratio A:B:C=1:2:3. If the longest side of ABC is 10 units, what is the perimeter of the triangle ABC?

      (3 pts) 5.

  • 6.

    Line L1 has the equation 3x2y=1 and passes through the point A(1,2). Line L2 is given by y=1 and intersects L1 at the point B. Line L3, which has a positive slope, passes through point A and intersects L2 at the point C. The area of ABC is 3. What is the slope of L3?

      (3 pts) 6.

  • 7.

    Let f1(x)=10x1 and fn(x)=f1(fn1(x)) for integers n2. What is the sum of the digits of f2025(1)?

      (3 pts) 7.

TOTAL POINTS

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Key Student Name

  • 1.

    Three cards are chosen at random from a standard 52-card deck. What is the probability that they are not all the same color? Express your answer as a simple fraction in lowest terms.

      (2 pts) 1. 13/17

  • 2.

    Find the exact value of

    22024+2202222020+22018

    Express your answer as a simple fraction in lowest terms.

      (3 pts) 2. 1/16

  • 3.

    What is the exact value of x+y for real numbers x and y satisfying the following equation?

    x2+y2=10x6y34

      (3 pts) 3. 2

  • 4.

    The real numbers a, b, and c form an arithmetic sequence with abc0. The quadratic ax2+bx+c has exactly one root. What is this root?

      (3 pts) 4. 2+3

  • 5.

    In a triangle ABC, the angles satisfy the ratio A:B:C=1:2:3. If the longest side of ABC is 10 units, what is the perimeter of the triangle ABC?

      (3 pts) 5. 15+53

  • 6.

    Line L1 has the equation 3x2y=1 and passes through the point A(1,2). Line L2 is given by y=1 and intersects L1 at the point B. Line L3, which has a positive slope, passes through point A and intersects L2 at the point C. The area of ABC is 3. What is the slope of L3?

      (3 pts) 6. 3/4

  • 7.

    Let f1(x)=10x1 and fn(x)=f1(fn1(x)) for integers n2. What is the sum of the digits of f2025(1)?

      (3 pts) 7. 16,201

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Solutions Student Name

  • 1.

    Three cards are chosen at random from a standard 52-card deck. What is the probability that they are not all the same color? Express your answer as a simple fraction in lowest terms.

      (2 pts) 1. 13/17

    Solution: Find the probability they are all same color, then subtract that from 1. There are 26 cards of each color, so 3 of them can be selected in (263) ways, and there are 2 colors. So the answer is 12(263)(523)=1317.

  • 2.

    Find the exact value of

    22024+2202222020+22018

    Express your answer as a simple fraction in lowest terms.

      (3 pts) 2. 1/16

    Solution: 22024(1+22)22020(1+22)=24=116.

  • 3.

    What is the exact value of x+y for real numbers x and y satisfying the following equation?

    x2+y2=10x6y34

      (3 pts) 3. 2

    Solution: The equation can be expressed as (x5)2+(y+3)2=0. Then x=5, y=3, and x+y=2.

  • 4.

    The real numbers a, b, and c form an arithmetic sequence with abc0. The quadratic ax2+bx+c has exactly one root. What is this root?

      (3 pts) 4. 2+3

    Solution: Let a=b+k and c=bk for some k>0. Since the quadratic has exactly one root, b24ac=0b24(b+k)(bk)=3b2+4k2=0k=32b. Then the root is b2a=b2(b+32b)=12+3=32.

  • 5.

    In a triangle ABC, the angles satisfy the ratio A:B:C=1:2:3. If the longest side of ABC is 10 units, what is the perimeter of the triangle ABC?

      (3 pts) 5. 15+53

    Solution: Let A=x, B=2x, and C=3x. Then x+2x+3x=180x=30. So the angles are A=30, B=60, and C=90, and ABC is a right triangle. Then, the side lengths are 5, 53, and 10, and the perimeter is 15+53.

  • 6.

    Line L1 has the equation 3x2y=1 and passes through the point A(1,2). Line L2 is given by y=1 and intersects L1 at the point B. Line L3, which has a positive slope, passes through point A and intersects L2 at the point C. The area of ABC is 3. What is the slope of L3?

      (3 pts) 6. 3/4

    Solution: The points A, B, and C form a triangle. The distance from the point A to L2 is 3, which is the height of the triangle, and the length of the line segment between B and C should be 2. Since L3 has a positive slope, the point C is at the point (3,1). Then the slope of L3 is d34.

  • 7.

    Let f1(x)=10x1 and fn(x)=f1(fn1(x)) for integers n2. What is the sum of the digits of f2025(1)?

      (3 pts) 7. 16,201

    Solution: f2(x)=10(10x1)1=102x101, f3(x)=103102101, , f2025(x)=102025x102024101. Then f2025(1)=888889 with 2024 eights and one nine. Thus, the sum of the digits is 82024+9=16,201.

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Student Name

  • 1.

    Two rectangles have the same perimeter. In the first rectangle the ratio of the long edge to the short edge is 2:1 and in the second rectangle these edges are in the ratio of 3:2. Then the ratio of the area of the first rectangle to the area of the second rectangle is

    (a) 2:3   (b) 25:6   (c) 25:27   (d) 27:2   (e) not determined

      (2 pts) 1.

  • 2.

    How many pairs of integers (x,y) satisfy the equation xy2x3y+1=0?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) infinitely many

      (3 pts) 2.

  • 3.

    Given square ABCD with side length 4, points E, F, G, and H are taken on sides AB, BC, CD, and DA, respectively, such that AE=BF=CG=DH. Determine the length of AE that minimizes the perimeter of quadrilateral EFGH.

    (a) 1    (b) 2    (c) 3    (d) 4    (e) 5

      (3 pts) 3.

  • 4.

    Let f be the function such that f(x)=ax4+bx3+cx2+dx+e satisfying f(1)=0 and f(x)f(x1)=2x(x+1)(2x+1) for any real number x. What is the value of 2025a+13b+c?

    (a) 2025    (b) 2042    (c) 2082    (d) 2100    (e) 2185

      (3 pts) 4.

  • 5.

    Chris’s garden is twice as large as Sarah’s garden and three times as large as James’s. James waters plants half as quickly as Sarah and one-third as quickly as Chris. If they all start watering their gardens at the same time, who will finish watering first?

    (a) Chris   (b) Sarah   (c) James and Chris tie for first
    (d) Sarah and James tie for first   (e) None of these

      (3 pts) 5.

  • 6.

    Peter has 250 students enrolled in his school club. He decides to form groups so that each group has a different number of students. The maximum number of groups he can form is:

    (a) 20    (b) 21    (c) 22    (d) 23    (e) none of these

      (3 pts) 6.

  • 7.

    For how many integers m0 is m2+7 a perfect square?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) no integer is satisfied

      (3 pts) 7.

TOTAL POINTS

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Key Student Name

  • 1.

    Two rectangles have the same perimeter. In the first rectangle the ratio of the long edge to the short edge is 2:1 and in the second rectangle these edges are in the ratio of 3:2. Then the ratio of the area of the first rectangle to the area of the second rectangle is

    (a) 2:3   (b) 25:6   (c) 25:27   (d) 27:2   (e) not determined

      (2 pts) 1. (c)

  • 2.

    How many pairs of integers (x,y) satisfy the equation xy2x3y+1=0?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) infinitely many

      (3 pts) 2. (d)

  • 3.

    Given square ABCD with side length 4, points E, F, G, and H are taken on sides AB, BC, CD, and DA, respectively, such that AE=BF=CG=DH. Determine the length of AE that minimizes the perimeter of quadrilateral EFGH.

    (a) 1    (b) 2    (c) 3    (d) 4    (e) 5

      (3 pts) 3. (b)

  • 4.

    Let f be the function such that f(x)=ax4+bx3+cx2+dx+e satisfying f(1)=0 and f(x)f(x1)=2x(x+1)(2x+1) for any real number x. What is the value of 2025a+13b+c?

    (a) 2025    (b) 2042    (c) 2082    (d) 2100    (e) 2185

      (3 pts) 4. (c)

  • 5.

    Chris’s garden is twice as large as Sarah’s garden and three times as large as James’s. James waters plants half as quickly as Sarah and one-third as quickly as Chris. If they all start watering their gardens at the same time, who will finish watering first?

    (a) Chris   (b) Sarah   (c) James and Chris tie for first
    (d) Sarah and James tie for first   (e) None of these

      (3 pts) 5. (b)

  • 6.

    Peter has 250 students enrolled in his school club. He decides to form groups so that each group has a different number of students. The maximum number of groups he can form is:

    (a) 20    (b) 21    (c) 22    (d) 23    (e) none of these

      (3 pts) 6. (b)

  • 7.

    For how many integers m0 is m2+7 a perfect square?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) no integer is satisfied

      (3 pts) 7. (a)

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Solutions Student Name

  • 1.

    Two rectangles have the same perimeter. In the first rectangle the ratio of the long edge to the short edge is 2:1 and in the second rectangle these edges are in the ratio of 3:2. Then the ratio of the area of the first rectangle to the area of the second rectangle is

    (a) 2:3   (b) 25:6   (c) 25:27   (d) 27:2   (e) not determined

      (2 pts) 1. (c)

    Solution. Let x and y represent the long and short edges of the first rectangle, respectively, while z and t represent the long and short edges of the second rectangle. We have x=2y, z=32t, and x+y=z+t, which implies that 3y=52t, or yt=56. The ratio of the area of the first rectangle to the area of the second rectangle is

    xyzt=2y232t2=43.(56)2=2527.
  • 2.

    How many pairs of integers (x,y) satisfy the equation xy2x3y+1=0?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) infinitely many

      (3 pts) 2. (d)

    Solution. We can rewrite the above equation as

    y(x3)=2x1y=2x1x3=2+5x3.

    Since y is an integer, 5 is divisible by x3, which implies that

    x3{1,1,5,5}x{2,2,4,8}.

    Therefore, there are 4 pairs of integers (x,y) satisfying the equation in question.

  • 3.

    Given square ABCD with side length 4, points E, F, G, and H are taken on sides AB, BC, CD, and DA, respectively, such that AE=BF=CG=DH. Determine the length of AE that minimizes the perimeter of quadrilateral EFGH.

    (a) 1    (b) 2    (c) 3    (d) 4    (e) 5

      (3 pts) 3. (b)

    Solution.

    DH4xAxE4xBFCG

    It is not difficult to verify that EFGH is a square. Let AE=x, then we must have AH=4x, which implies by the Pythagorean theorem that

    EH2=x2+(4x)2=2x28x+16=2(x2)2+88.

    Therefore, the perimeter of EFGH attains minimum value if and only if x=2.

  • 4.

    Let f be the function such that f(x)=ax4+bx3+cx2+dx+e satisfying f(1)=0 and f(x)f(x1)=2x(x+1)(2x+1) for any real number x. What is the value of 2025a+13b+c? (a) 2025    (b) 2042    (c) 2082    (d) 2100    (e) 2185

      (3 pts) 4. (c)

    Solution. Because f(1)=0 and f(x)f(x1)=2x(x+1)(2x+1), we deduce that

    f(0)=f(1)=0,f(1)=f(2)=0.

    Therefore, we can write

    f(x)=x(x+1)(x+2)(mx+n),

    for some real numbers m and n. Again, using the fact that f(x)f(x1)=2x(x+1)(2x+1), we have

    f(1)f(0)=12,f(2)f(1)=60,

    or

    6m+6n=12,42m+18n=60,

    which implies that m=n=1. Therefore,

    f(x)=x(x+1)(x+2)(x+1)=x4+4x3+5x2+2x.

    This means that a=1,b=4,c=5,d=2,e=0. So, (c) is the correct answer.

  • 5.

    Chris’s garden is twice as large as Sarah’s garden and three times as large as James’s. James waters plants half as quickly as Sarah and one-third as quickly as Chris. If they all start watering their gardens at the same time, who will finish watering first?

    (a) Chris   (b) Sarah   (c) James and Chris tie for first
    (d) Sarah and James tie for first   (e) None of these

      (3 pts) 5. (b)

    Solution. Let the size of James’s garden be x. Then:

    • Chris’s garden size is 3x,

    • Sarah’s garden size is 3x2.

    The watering rates are:

    • James: r,

    • Sarah: 2r,

    • Chris: 3r.

    The time to water each garden is:

    James: xr,  Sarah: 3x22r=3x4r,  Chris: 3x3r=xr.

    Clearly, 3x4r<xr, so Sarah will finish watering first.

  • 6.

    Peter has 250 students enrolled in his school club. He decides to form groups so that each group has a different number of students. The maximum number of groups he can form is:

    (a) 20    (b) 21    (c) 22    (d) 23    (e) none of these

      (3 pts) 6. (b)

    Solution. To find the maximum number of groups Peter can form such that each group has a different number of students and the total number of students is 250, we solve the inequality:

    n(n+1)2250.

    Rewriting:

    n(n+1)500.

    Solving the quadratic equation n2+n500=0 using the quadratic formula:

    n=1±1+45002=1±20012.

    Note that 2001<2025=45, we get:

    n<1+452=22.

    Thus, the largest integer n is 21.

  • 7.

    For how many integers m0 is m2+7 a perfect square?

    (a) 1    (b) 2    (c) 3    (d) 4    (e) no integer is satisfied

      (3 pts) 7. (a)

    Solution. m2+7 is a perfect square if it can be written as

    m2+7=n2n2m2=7,

    for some integer n. This is equivalent to

    (nm)(n+m)=7.

    We have the following possibilities:

    nm=1,n+m=7 n=4,m=3,
    nm=7,n+m=1 n=4,m=3,
    nm=1,n+m=7 n=4,m=3,
    nm=7,n+m=1 n=4,m=3.

    In conclusion, there is only 1 number m0 satisfying the requirement of the question. So, (a) is the correct answer.

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #3

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Student Name

  • 1.

    Alex needs to create a four-digit code for his locker. The digits must be selected from the set {0,1,2,3,4,5,6,7,8,9}, and they must be distinct. To make it easier to remember, Alex decides to arrange the digits in strictly decreasing order. For instance, the code 9530 follows this rule. How many different four-digit codes can Alex choose?

      (2 pts) 1.

  • 2.

    Elsa shopped at a store where each item costs either $1.00 or 49 cents. She spent a total of $39.84 How many items did she purchase?

      (3 pts) 2.

  • 3.

    What is the coefficient of the x3y7 term in the expansion of (2x+y)10 ?

      (3 pts) 3.

  • 4.

    If you draw four lines in the plane, they divide the plane into some number of regions. What is the maximum number of regions you can get?

      (3 pts) 4.

  • 5.

    What is the smallest positive integer x such that x2 has 2024 as a factor?

      (3 pts) 5.

  • 6.

    The arithmetic mean A, of any two positive numbers x and y is defined to be A=12(x+y) and their geometric mean, G is defined to be G=xy. For two particular values x and y, with x>y, the ratio A:G=5:4. For these values of x and y, what is the ratio x:y ?

      (3 pts) 6.

  • 7.

    The diagram shows a square ABCD and a right-angled triangle ABE. The length of BC is 4 and the length of BE is 5. What is the area of the shaded region?

    BCEDA

      (3 pts) 7.

TOTAL POINTS

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #3

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Key Student Name

  • 1.

    Alex needs to create a four-digit code for his locker. The digits must be selected from the set {0,1,2,3,4,5,6,7,8,9}, and they must be distinct. To make it easier to remember, Alex decides to arrange the digits in strictly decreasing order. For instance, the code 9530 follows this rule. How many different four-digit codes can Alex choose?

      (2 pts) 1. 210

  • 2.

    Elsa shopped at a store where each item costs either $1.00 or 49 cents. She spent a total of $39.84 How many items did she purchase?

      (3 pts) 2. 32+16=48

  • 3.

    What is the coefficient of the x3y7 term in the expansion of (2x+y)10 ?

      (3 pts) 3. 960

  • 4.

    If you draw four lines in the plane, they divide the plane into some number of regions. What is the maximum number of regions you can get?

      (3 pts) 4. 11

  • 5.

    What is the smallest positive integer x such that x2 has 2024 as a factor?

      (3 pts) 5. 1012

  • 6.

    The arithmetic mean A, of any two positive numbers x and y is defined to be A=12(x+y) and their geometric mean, G is defined to be G=xy. For two particular values x and y, with x>y, the ratio A:G=5:4. For these values of x and y, what is the ratio x:y ?

      (3 pts) 6. 4:1

  • 7.

    The diagram shows a square ABCD and a right-angled triangle ABE. The length of BC is 4 and the length of BE is 5. What is the area of the shaded region?

    BCEDA

      (3 pts) 7. 485 or 9.6

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #4

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Student Name

  • 1.

    A box contains 50 balls numbered 1 through 50. Jake draws a ball at random, then Sally draws a ball at random from the remaining 49. If the product of the numbers they draw is even, Sally wins. If the product is odd, Jake wins. Which of the following is true?

    1. a.

      Jake is more likely to win.

    2. b.

      Jake and Sally are equally likely to win.

    3. c.

      Sally is more likely to win.

      (2 pts) 1.

  • 2.

    What is the area of the shaded region inside the square?

    113

      (3 pts) 2.

  • 3.

    If a is a positive number and x4+16=(x2+ax+4)(x2ax+4), find a.

      (3 pts) 3.

  • 4.

    Find x if x is positive and: x=11x+3+1x+12.

      (3 pts) 4.

  • 5.

    Compute 242+25+24

      (3 pts) 5.

  • 6.

    Find the length of side x given the information in the picture.

    22221x

      (3 pts) 6.

  • 7.

    Compute 19021982

      (3 pts) 7.

TOTAL POINTS

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #4

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Key Student Name

  • 1.

    A box contains 50 balls numbered 1 through 50. Jake draws a ball at random, then Sally draws a ball at random from the remaining 49. If the product of the numbers they draw is even, Sally wins. If the product is odd, Jake wins. Which of the following is true?

    1. a.

      Jake is more likely to win.

    2. b.

      Jake and Sally are equally likely to win.

    3. c.

      Sally is more likely to win.

      (2 pts) 1. c

  • 2.

    What is the area of the shaded region inside the square?

    113

      (3 pts) 2. 6

  • 3.

    If a is a positive number and x4+16=(x2+ax+4)(x2ax+4), find a.

      (3 pts) 3. 22 or 8

  • 4.

    Find x if x is positive and: x=11x+3+1x+12.

      (3 pts) 4. 6

  • 5.

    Compute 242+25+24

      (3 pts) 5. 25

  • 6.

    Find the length of side x given the information in the picture.

    22221x

      (3 pts) 6. 5

  • 7.

    Compute 19021982

      (3 pts) 7. 379

UND MATHEMATICS TRACK MEET INDIVIDUAL TEST #4

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Solutions Student Name

  • 1.

    A box contains 50 balls numbered 1 through 50. Jake draws a ball at random, then Sally draws a ball at random from the remaining 49. If the product of the numbers they draw is even, Sally wins. If the product is odd, Jake wins. Which of the following is true?

    1. a.

      Jake is more likely to win.

    2. b.

      Jake and Sally are equally likely to win.

    3. c.

      Sally is more likely to win.

    Solution: Jake only wins if both numbers are odd. The chances of that are:

    12(2449)=2498<12
  • 2.

    What is the area of the shaded region inside the square?

    113

    Solution: The shaded area is: 92(12(3)(1))=6

  • 3.

    If a is a positive number and x4+16=(x2+ax+4)(x2ax+4), find a.

    Solution: Note that

    x4+16 =(x2+ax+4)(x2ax+4)
    =(x2+4)2(ax)2
    =x4+8x2+16a2x2 =x4+(8a2)x2+16

    So we need a>0 with a2=8, hence a=22.

  • 4.

    Find x if x is positive and: x=11x+3+1x+12.
    Solution:

    x=(x+12)(x+3)x+3+x+12 =x2+15x+362x+15
    2x2+15x =x2+15x+36
    x2 =36

    Since x is positive, x=6.

  • 5.

    Compute 242+25+24
    Solution:

    242+25+24=24(24+1)+25=24(25)+25=25(1+24)=252=25
  • 6.

    Find the length of side x given the information in the picture.

    22221x43

    Solution: Using the Pythagorean Theorem we have:

    x=42+32=5
  • 7.

    Compute 19021982
    Solution:

    19021982=(190+189)(190189)=(379)(1)=379

UND MATHEMATICS TRACK MEET TEAM TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed.

  • 1.

    A rectangular piece of plywood is 3.6 feet wide and 7.2 feet long. Find the area of the piece of plywood. Round your answer to one decimal place. Express your answer in square feet.

      (20 pts) 1.

  • 2.

    A used car dealer has six cars to sell. Two of the cars are red, and the other four cars are white. The dealer wishes to park all six of the cars in a row in front of the showroom building. The row of cars will be along the street, and all six cars will face the street. The dealer has enough space to park six cars along the street, but no more than six cars. The two red cars must be parked adjacent to each other. How many arrangements of the six cars are possible?

      (20 pts) 2.

  • 3.

    A large bowl contains 22 balls. All of the balls are of the same size and shape, and all are made of the same material. Of the 22 balls, 9 are red, 7 are white, and 6 are blue. Suppose that we randomly select two of the 22 balls and place both of the selected balls together in a different bowl. What is the probability that neither of the selected balls is red?

      (20 pts) 3.

  • 4.

    Mrs. Noriega is designing a box. The box is to have six sides. Each of the six sides is to be a rectangle. The dimensions of the box, in inches, are to be x by 122x by 92x. Here x is a number which Mrs. Noriega has not yet determined. Find the value of x which will result in the box with the largest possible volume. Round your answer to two decimal places. Hint: All three of the dimensions of the box must be positive real numbers.

      (20 pts) 4.

  • 5.

    The cost of a ticket for a certain baseball game was $25. Children under the age of 18 received a discount, however. The cost of a “youth” ticket was $17. The team sold 748 tickets for the game. The total sales revenue for these 748 tickets was $17,532. How many youth tickets did the team sell?

      (20 pts) 5.

  • 6.

    What is the area of the region in the xy-plane whose points (x,y) satisfy the following inequality?

    |x|+|y|+|x+y|2

      (20 pts) 6.

  • 7.

    Mrs. Ramaphosa drives ten miles to work each day. She leaves for work at the same time every morning and arrives at work at exactly 8:00 A.M. Her average travel speed each morning is 40 miles per hour. One morning, however, the traffic is congested. After Mrs. Ramaphosa has traveled exactly two miles, she determines that her average speed up to that point has been only 24 miles per hour. If Mrs. Ramaphosa is to arrive at work at exactly 8:00 A.M., what must her average speed for the remaining 8 miles of the trip be? Hint: Find the required average speed for the last 8 miles of the trip only.

      (20 pts) 7.

  • 8.

    Suppose that two sides of an isosceles triangle have length 3, and let x equal the length of the third side of the triangle. What value of x will produce a triangle with the largest possible area? Round your answer to two decimal places.

      (20 pts) 8.

  • 9.

    A disk is a circle together with the points inside the circle. Suppose that disks of equal radii are arranged in a regular pattern throughout the plane in such a way that each disk touches and is tangent to six other disks. What percentage of the plane is covered by the disks? Round your answer to two decimal places. For example, your answer might be 72.34%, 47.83%, or something similar to these percentages.

      (20 pts) 9.

  • 10.

    Four solid spheres lie on the top of a table. Each sphere is tangent to each of the other three spheres. Three of the four spheres have radius 4 cm, and the other sphere has a radius of less than 4 cm. What is the radius of the smaller sphere? Round your answer to two decimal places.

      (20 pts) 10.

TOTAL POINTS

UND MATHEMATICS TRACK MEET TEAM TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Key

  • 1.

    A rectangular piece of plywood is 3.6 feet wide and 7.2 feet long. Find the area of the piece of plywood. Round your answer to one decimal place. Express your answer in square feet.

      (20 pts) 1. 25.9 sq ft

  • 2.

    A used car dealer has six cars to sell. Two of the cars are red, and the other four cars are white. The dealer wishes to park all six of the cars in a row in front of the showroom building. The row of cars will be along the street, and all six cars will face the street. The dealer has enough space to park six cars along the street, but no more than six cars. The two red cars must be parked adjacent to each other. How many arrangements of the six cars are possible?

      (20 pts) 2. 240

  • 3.

    A large bowl contains 22 balls. All of the balls are of the same size and shape, and all are made of the same material. Of the 22 balls, 9 are red, 7 are white, and 6 are blue. Suppose that we randomly select two of the 22 balls and place both of the selected balls together in a different bowl. What is the probability that neither of the selected balls is red?

      (20 pts) 3. 0.338 or 0.34 or 33.8% or 34% or 2677, but not 0.3 or 310

  • 4.

    Mrs. Noriega is designing a box. The box is to have six sides. Each of the six sides is to be a rectangle. The dimensions of the box, in inches, are to be x by 122x by 92x. Here x is a number which Mrs. Noriega has not yet determined. Find the value of x which will result in the box with the largest possible volume. Round your answer to two decimal places. Hint: All three of the dimensions of the box must be positive real numbers.

      (20 pts) 4. 1.70

  • 5.

    The cost of a ticket for a certain baseball game was $25. Children under the age of 18 received a discount, however. The cost of a “youth” ticket was $17. The team sold 748 tickets for the game. The total sales revenue for these 748 tickets was $17,532. How many youth tickets did the team sell?

      (20 pts) 5. 146

  • 6.

    What is the area of the region in the xy-plane whose points (x,y) satisfy the following inequality?

    |x|+|y|+|x+y|2

      (20 pts) 6. 3

  • 7.

    Mrs. Ramaphosa drives ten miles to work each day. She leaves for work at the same time every morning and arrives at work at exactly 8:00 A.M. Her average travel speed each morning is 40 miles per hour. One morning, however, the traffic is congested. After Mrs. Ramaphosa has traveled exactly two miles, she determines that her average speed up to that point has been only 24 miles per hour. If Mrs. Ramaphosa is to arrive at work at exactly 8:00 A.M., what must her average speed for the remaining 8 miles of the trip be? Hint: Find the required average speed for the last 8 miles of the trip only.

      (20 pts) 7. 48 mph

  • 8.

    Suppose that two sides of an isosceles triangle have length 3, and let x equal the length of the third side of the triangle. What value of x will produce a triangle with the largest possible area? Round your answer to two decimal places.

      (20 pts) 8. 4.24

  • 9.

    A disk is a circle together with the points inside the circle. Suppose that disks of equal radii are arranged in a regular pattern throughout the plane in such a way that each disk touches and is tangent to six other disks. What percentage of the plane is covered by the disks? Round your answer to two decimal places. For example, your answer might be 72.34%, 47.83%, or something similar to these percentages.

      (20 pts) 9. 90.69%

  • 10.

    Four solid spheres lie on the top of a table. Each sphere is tangent to each of the other three spheres. Three of the four spheres have radius 4 cm, and the other sphere has a radius of less than 4 cm. What is the radius of the smaller sphere? Round your answer to two decimal places.

      (20 pts) 10. 1.33cm

UND MATHEMATICS TRACK MEET TEAM TEST #1

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are allowed. Solutions

  • 1.

    A rectangular piece of plywood is 3.6 feet wide and 7.2 feet long. Find the area of the piece of plywood. Round your answer to one decimal place. Express your answer in square feet.

    Solution: 3.67.2=25.9225.9

  • 2.

    A used car dealer has six cars to sell. Two of the cars are red, and the other four cars are white. The dealer wishes to park all six of the cars in a row in front of the showroom building. The row of cars will be along the street, and all six cars will face the street. The dealer has enough space to park six cars along the street, but no more than six cars. The two red cars must be parked adjacent to each other. How many arrangements of the six cars are possible?

    Solution: Think of the six parking places along the street. We may number these parking places from 1 to 6. The leftmost of the red cars can be in spots 1, 2, 3, 4, or 5. There are 2 ways of arranging the two red cars in this spot and its neighbor to the right. There are 4321=24 ways to arrange the four white cars in the four slots not occupied by red cars. The number of ways of arranging the six cars is thus 5224=240.

  • 3.

    A large bowl contains 22 balls. All of the balls are of the same size and shape, and all are made of the same material. Of the 22 balls, 9 are red, 7 are white, and 6 are blue. Suppose that we randomly select two of the 22 balls and place both of the selected balls together in a different bowl. What is the probability that neither of the selected balls is red?

    Solution: Imagine that we select the two balls one at a time. The probability that the first ball is not red is 1322. The probability that the second ball is not red, given that the first ball was not red is 1221. The probability that neither ball is red is 13221221=132117=27770.338.

  • 4.

    Mrs. Noriega is designing a box. The box is to have six sides. Each of the six sides is to be a rectangle. The dimensions of the box, in inches, are to be x by 122x by 92x. Here x is a number which Mrs. Noriega has not yet determined. Find the value of x which will result in the box with the largest possible volume. Round your answer to two decimal places. Hint: All three of the dimensions of the box must be positive real numbers.

    Solution: We require x>0, 122x>0, and 92x>0. Thus x<6 and x<4.5, so that 0<x<4.5. The volume of the box will be V(x)=x(122x)(92x). Graphing V(x) and zooming in, we find that the maximum value of V occurs when x=1.70.

  • 5.

    The cost of a ticket for a certain baseball game was $25. Children under the age of 18 received a discount, however. The cost of a “youth” ticket was $17. The team sold 748 tickets for the game. The total sales revenue for these 748 tickets was $17,532. How many youth tickets did the team sell?

    Solution: Let x be the number of adult tickets sold and y be the number of youth tickets sold. Then

    x+y =748 (3.1)
    25x+17y =17532. (3.2)

    By (3.1), x=748y. Plugging this into (3.2), we find that

    25(748y)+17y =17532
    1870025y+17y =17532
    1870017532 =8y
    1168 =8y
    146 =y
  • 6.

    What is the area of the region in the xy-plane whose points (x,y) satisfy the following inequality?

    |x|+|y|+|x+y|2

    Solution: In quadrant I, x,y0 and the summands are already positive. Therefore, 2x+2y2, which is the triangle with vertices (0,1), (1,0), and the origin. This has area 12.

    In quadrant II: when x+y0, the inequality becomes x+y+x+y2, so that y1. When x+y0, the inequality becomes x+yxy2 so that 2x2 and x1. This describes the square with vertices (1,0), (1,1), (0,1), and the origin, which has area 1.

    In quadrant III, the summands are all negative, so that 2x2y2 and x+y1. This is the triangle with vertices (1,0), (0,1), and the origin, which has area 12.

    In quadrant IV: when x+y0, the inequality becomes xy+x+y2, so that x1. When x+y0, the inequality becomes xyxy2, so that 2y2 and y1. This describes the square with vertices (1,0), (1,1), (0,1), and the origin, which has area 1.

    The total area of the original region is 12+1+12+1=3.

  • 7.

    Mrs. Ramaphosa drives ten miles to work each day. She leaves for work at the same time every morning and arrives at work at exactly 8:00 A.M. Her average travel speed each morning is 40 miles per hour. One morning, however, the traffic is congested. After Mrs. Ramaphosa has traveled exactly two miles, she determines that her average speed up to that point has been only 24 miles per hour. If Mrs. Ramaphosa is to arrive at work at exactly 8:00 A.M., what must her average speed for the remaining 8 miles of the trip be? Hint: Find the required average speed for the last 8 miles of the trip only.

    Solution: If Mrs. Ramaphosa’s average speed is 40 miles per hour, then it takes her

    10miles×1hour40miles=14hour

    to drive to work, and she leaves for work at 7:45 A.M. each day. For the morning in question, she has traveled 2 miles after

    2miles×1hour24miles×60minutes1hour=5minutes

    or 7:50 A.M. If Mrs. Ramaphosa is to arrive at work at exactly 8:00 A.M., she must cover the remaining 8 miles of her trip to work in exactly 10 minutes. Her average speed for the remainder of the trip must be

    8miles10minutes×60minutes1hour=48mileshour.
  • 8.

    Suppose that two sides of an isosceles triangle have length 3, and let x equal the length of the third side of the triangle. What value of x will produce a triangle with the largest possible area? Round your answer to two decimal places.

    Solution: By the Pythagorean Theorem, the height of the triangle is h=9x2/4, so that the area is A=12x9x2/4. The area is maximized by maximizing

    16A2=x2(36x2)=x4+36x2=(x436x2+182)+182=(x218)2+182.

    This happens when x=18=324.24

  • 9.

    A disk is a circle together with the points inside the circle. Suppose that disks of equal radii are arranged in a regular pattern throughout the plane in such a way that each disk touches and is tangent to six other disks. What percentage of the plane is covered by the disks? Round your answer to two decimal places. For example, your answer might be 72.34%, 47.83%, or something similar to these percentages.

    Solution: Consider an equilateral triangle whose vertices are the centers of three mutually adjacent disks. We can rearrange the portion covered by the disks to see that this has area πr22. The triangle has base 2r and height r3, so that its area is r23. We can cover the plane with these triangles, so that the percentage covered is

    12πr2r23×100%=π36×100%90.60%.
  • 10.

    Four solid spheres lie on the top of a table. Each sphere is tangent to each of the other three spheres. Three of the four spheres have radius 4 cm, and the other sphere has a radius of less than 4 cm. What is the radius of the smaller sphere? Round your answer to two decimal places.

    Solution: The centers of the larger spheres forms an equilateral triangle with side length 8. The smaller sphere is centered at the center of the triangle, so that where it touches the table is 8/3 from where each larger sphere touches the table.

    Suppose the smaller sphere has radius r, so that its center is 4+r from the center of a larger sphere. Because the centers are horizontally 8/3 apart, and vertically 4r apart, the Pythagorean Theorem tells us that

    (4+r)2 =(4r)2+(8/3)2
    42+8r+r2 =428r+r2+643
    16r =643
    r =431.33

UND MATHEMATICS TRACK MEET TEAM TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed.

  • 1.

    Recall i2=1. Simplify (1+i)8 as much as possible.

      (20 pts) 1.

  • 2.

    What is the average of the three solutions to x3+6x28x16?

      (20 pts) 2.

  • 3.

    Find all positive values for a radius of a circle for which the area of the circle is equal numerically to twice its circumference.

      (20 pts) 3.

  • 4.

    Find all solutions to x1=2x+1.

      (20 pts) 4.

  • 5.

    Assume today is Friday. What day of the week will it be in 365 days?

      (20 pts) 5.

  • 6.

    How many edges does a tetrahedron have?

      (20 pts) 6.

  • 7.

    How many real roots does the equation cosx=log10x have?

      (20 pts) 7.

  • 8.

    Sort the integers 1 through 4 randomly, and denote them as a, b, c, and d. What is the probability that ab+cd is an even number?

      (20 pts) 8.

  • 9.

    A penny is placed flat on a table. What is the maximum number of pennies that can be places around it, flat on the table, with each one tangent to it?

      (20 pts) 9.

  • 10.

    In a group of dogs and people, the number of legs was 14 more than twice the number of heads. How many dogs were there? [Assume none of the people or dogs is missing a leg or has an extra.]

      (20 pts) 10.

TOTAL POINTS

UND MATHEMATICS TRACK MEET TEAM TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Key

  • 1.

    Recall i2=1. Simplify (1+i)8 as much as possible.

      (20 pts) 1. 16

  • 2.

    What is the average of the three solutions to x3+6x28x16?

      (20 pts) 2. 2

  • 3.

    Find all positive values for a radius of a circle for which the area of the circle is equal numerically to twice its circumference.

      (20 pts) 3. 4

  • 4.

    Find all solutions to x1=2x+1.

      (20 pts) 4. x=4

  • 5.

    Assume today is Friday. What day of the week will it be in 365 days?

      (20 pts) 5. Saturday

  • 6.

    How many edges does a tetrahedron have?

      (20 pts) 6. 6

  • 7.

    How many real roots does the equation cosx=log10x have?

      (20 pts) 7. 3

  • 8.

    Sort the integers 1 through 4 randomly, and denote them as a, b, c, and d. What is the probability that ab+cd is an even number?

      (20 pts) 8. 23

  • 9.

    A penny is placed flat on a table. What is the maximum number of pennies that can be places around it, flat on the table, with each one tangent to it?

      (20 pts) 9. 6

  • 10.

    In a group of dogs and people, the number of legs was 14 more than twice the number of heads. How many dogs were there? [Assume none of the people or dogs is missing a leg or has an extra.]

      (20 pts) 10. 7

UND MATHEMATICS TRACK MEET TEAM TEST #2

University of North Dakota Grades 11/12

January 13, 2025

School Team Name

Calculators are NOT allowed. Solutions

  • 1.

    Recall i2=1. Simplify (1+i)8 as much as possible.

      (20 pts) 1. 16

    Solution: Observe (1+i)2=1+2i+i2=2i and so (1+i)8=((1+i)2)4=(2i)4=16i4=16.

  • 2.

    What is the average of the three solutions to x3+6x28x16?

      (20 pts) 2. 2

    Solution: Denote the three solutions to x3+6x28x16 by r1, r2, and r3. By Viete’s formula, r1+r2+r3=6. Thus, r1+r2+r33=63=2.

  • 3.

    Find all positive values for a radius of a circle for which the area of the circle is equal numerically to twice its circumference.

      (20 pts) 3. 4

    Solution: Let r be the radius of a circle. The condition A=2C for the area A and circumference C can be expressed in terms of r as πr2=2(2πr). Rearranging gives πr24πr=0 or equivalently πr(r4)=0. The only positive solution to the latter is r=4.

  • 4.

    Find all solutions to x1=2x+1.

      (20 pts) 4. x=4

    Solution: Observe

    x1 =2x+1
    (x1)2 =2x+1
    x22x+1 =2x+1
    x24x =0
    x(x4) =0

    which has solutions x=0 and x=4. Checking each in the original equation, we verify that x=4 is a solution and that x=0 is not a solution. Thus x=4 is the only solution.

  • 5.

    Assume today is Friday. What day of the week will it be in 365 days?

      (20 pts) 5. Saturday

    Solution: Observe 365=527+1, so 365 days after Friday is the same as 1 day after Friday. This is Saturday.

  • 6.

    How many edges does a tetrahedron have?

      (20 pts) 6. 6

    Solution: A tetrahedron is a platonic solid with four triangular faces and 6 edges.

  • 7.

    How many real roots does the equation cosx=log10x have?

      (20 pts) 7. 3

    Solution: Observe that |cosx|1 and log10x>1 for x>10, so that any solutions occur in the interval (0,10). Now log10x0 for 0<x1 and cosx>0 on (0,π/2). Thus there are no solutions in the interval (0,1]. On (1,10], we have 0<log10x1. There is one solution in the interval (1,π/2) and two more solutions in the interval (3π/2,5π/2). Noting that 7π/2>10, there are no additional solutions. In summary, there are three solutions, namely x1.418,5.552,6.863 to three digit places.

  • 8.

    Sort the integers 1 through 4 randomly, and denote them as a, b, c, and d. What is the probability that ab+cd is an even number?

      (20 pts) 8. 23

    Solution: There are 4! possible ways to assign values to a, b, c, and d. We count the ways for which ab+cd is odd. This requires that ab or cd is odd. Now ab is odd in 2!2!=4 ways. Similarly, cd is odd in 2!2!=4 ways. Thus there are 8 ways for ab+cd to be odd. So, there are 248=16 ways for ab+cd to be even. We conclude that the probability that ab+cd is an even number is 1624=23.

  • 9.

    A penny is placed flat on a table. What is the maximum number of pennies that can be places around it, flat on the table, with each one tangent to it?

      (20 pts) 9. 6

    Solution: When two pennies are placed around the original penny, the line segments between the centers of the three coins form an equilateral triangle. Thus the central angle formed between the two placed is 60 degrees with respect to the center penny. It follows that the number of pennies which can be placed is 360/60 = 6.

  • 10.

    In a group of dogs and people, the number of legs was 14 more than twice the number of heads. How many dogs were there? [Assume none of the people or dogs is missing a leg or has an extra.]

      (20 pts) 10. 7

    Solution: Let d and p be the number of dogs and people respectively. Then 4d+2p=2(d+p)+14. Thus 2d=14 and d=7. There are 7 dogs.

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