Chapter B

Exercises B.0

  1. 1.

    80⁢x12⁢y17

  2. 2.

    a16⁢b7

  3. 3.

    x316⁢y22⁢z35

  4. 4.

    x2⁢y4⁢z5⁢z4=x2⁢y4⁢z21/4

  5. 5.

    3⁢x⁢(x2+9⁢x+3)

  6. 6.

    5⁢(x−1)3⁢x13

  7. 7.

    −5⁢x+42⁢x12⁢(x+4)2

  8. 8.

    6⁢x⁢(3⁢x2+2)3⁢(x2−5)2⁢(7⁢x2−18)

  9. 9.

    • 8

      44

      x2−6⁢x+8

      x2+2⁢x−4

  10. 10.

    • −13

      undefined

      1x−2−5

      1x−5−2

  11. 11.

    • Possible solution: f⁢(x)=5x and g⁢(x)=x+4

      Possible solution: f⁢(x)=|x| and g⁢(x)=4−x2

      Possible solution: f⁢(x)=x−5 and g⁢(x)=(x+2)2

  12. 12.

    • Possible solution: f⁢(x)=x3, g⁢(x)=x2, and h⁢(x)=2⁢x+1

      Possible solution: f⁢(x)=2⁢x+1, g⁢(x)=x3, and h⁢(x)=x2

Exercises B.1

  1. 1.

    T

  2. 2.

    Answers will vary.

  3. 3.

    Answers will vary.

  4. 4.

    Answers will vary.

  5. 5.

    (a) f′⁢(x)=0, (b) y=6

  6. 6.

    (a) f′⁢(x)=2, (b) y=2⁢x

  7. 7.

    (a) f′⁢(x)=−3, (b) y=4−3⁢x

  8. 8.

    (a) g′⁢(x)=2⁢x, (b) y=−4⁢x−4

  9. 9.

    (a) h′⁢(x)=2−2⁢x (b) y=1

  10. 10.

    (a) f′′⁢(x)=6⁢x−1, (b) y=−7⁢x+1

  11. 11.

    (a) g′⁢(x)=12⁢x+3, (b) y=x4+74

  12. 12.

    (a) r′⁢(x)=−1x2, (b) y=−x4−1

  13. 13.

    (a) h′⁢(x)=−32⁢x⁢x, (b) y=−3⁢x16+94

  14. 14.

    (a) f′⁢(x)=−1(s−2)2, (b) y=−x+4

  15. 15.

    f⁢(x)=x, c=16.

  16. 16.

    f⁢(x)=x4, c=3

  17. 17.

    f⁢(x)=1x, c=2

  18. 18.

    f⁢(x)=cos⁡x, c=−π.

  19. 19.

    y=8.1⁢(x−3)+16

  20. 20.

    y=.248⁢x+1.006

  21. 21.

    y=−0.099⁢(x−9)+1

  22. 22.

    y=7.77⁢(x−2)+e2, or y=7.77⁢(x−2)+7.39

  23. 23.

    y=.49⁢(x−2)+ln⁡2

  24. 24.

    y=−0.05⁢x+1

  25. 25.

    • Approximations will vary; they should match (c) closely.

      f′⁢(x)=2⁢x

      At (−1,0), slope is −2. At (0,−1), slope is 0. At (2,3), slope is 4.

  26. 26.

    • Approximations will vary; they should match (c) closely.

      f′⁢(x)=−1/(x+1)2

      At (0,1), slope is −1. At (1,0.5), slope is −1/4.

  27. 27.

    −2−11234−1123xy
  28. 28.

    −6−4−22−22xy
  29. 29.

    −2−112−55xy
  30. 30.

    −1−0.50.51−2⁢π−ππ2⁢πxy
  31. 31.

    −2−112−33−22−44−66xy
  32. 32.

    −55510xy
  33. 33.

    • Approximately on (−2,0) and (2,∞).

      Approximately on (−∞,−2) and (0,2).

      Approximately at x=0,±2.

      Approximately on (−∞,−1) and (1,∞).

      Approximately on (−1,1).

      Approximately at x=±1.

  34. 34.

    • Approximately on (−1.5,1.5).

      Approximately on (−∞,−1.5)∪(1.5,∞).

      Approximately at x=±1.5.

      On (−∞,−1)∪(0,1).

      On (−1,0)∪(1,∞).

      At x=±1 and x=0.

  35. 35.
  36. 36.

    Approximately −24.

  37. 37.

    Approximately 0.54.

  38. 38.

    • (−∞,∞)

      (−∞,−1)∪(−1,1)∪(1,∞)

      (−∞,5]

      [−5,5]

  39. 39.

    • 1

      3

      Does not exist

      (−∞,−3)∪(3,∞)

Exercises B.2

  1. 1.

    Velocity

  2. 2.

    Answers will vary.

  3. 3.

    Linear functions.

  4. 4.

    12

  5. 5.

    −17

  6. 6.

    102

  7. 7.

    f⁢(10.1) is likely most accurate, as accuracy is lost the farther from x=10 we go.

  8. 8.

    −4

  9. 9.

    6

  10. 10.

    decibels per person

  11. 11.

    ft/s2

  12. 12.

    ft/h

  13. 13.

    • thousands of dollars per car

      It is likely that P⁢(0)<0. That is, negative profit for not producing any cars.

  14. 14.

    • degrees Fahrenheit per hour

      It is likely that T′⁢(8)>0 since at 8 in the morning, the temperature is likely rising.

      It is very likely that T⁢(8)>0, as at 8 in the morning on July 4, we would expect the temperature to be well above 0.

  15. 15.

    f⁢(x)=g′⁢(x)

  16. 16.

    g⁢(x)=f′⁢(x)

  17. 17.

    g⁢(x)=f′⁢(x)

  18. 18.

    g⁢(x)=f′⁢(x)

  19. 19.

    f⁢(6)=1, f′⁢(6)=−34

  20. 20.

    Answers vary. Possible solution

    123−3−2−112xy
  21. 21.

    Answers vary. Possible solution

    123−1123xy
  22. 22.

    x=±1

  23. 23.

    f′⁢(x)=10⁢x

  24. 24.

    f′⁢(x)=3⁢x2−12⁢x+12

  25. 25.

    f′⁢(π)≈0.

  26. 26.

    f′⁢(9)≈0.1667.

Exercises B.3

  1. 1.

    Power Rule.

  2. 2.

    1/x

  3. 3.

    One answer is f⁢(x)=10⁢ex.

  4. 4.

    One answer is f⁢(x)=10.

  5. 5.

    f⁢(x), g⁢(x), h⁢(x), and m⁢(x)

  6. 6.

    Answers will vary.

  7. 7.

    One possible answer is f⁢(x)=17⁢x−205.

  8. 8.

    Answers will vary.

  9. 9.

    f′⁢(x) is a velocity function, and f′′⁢(x) is acceleration.

  10. 10.

    lbs/ft2.

  11. 11.

    f′⁢(x)=14⁢x−5

  12. 12.

    g′⁢(x)=42⁢x2+14⁢x+11

  13. 13.

    m′⁢(t)=45⁢t4−38⁢t2+3

  14. 14.

    f′⁢(θ)=9⁢cos⁡θ−10⁢sin⁡θ

  15. 15.

    f′⁢(r)=6⁢er

  16. 16.

    g′⁢(t)=40⁢t3+sin⁡t+7⁢cos⁡t

  17. 17.

    f′⁢(x)=2x−1

  18. 18.

    p′⁢(s)=s3+s2+s+1

  19. 19.

    h′⁢(t)=et−cos⁡t+sin⁡t

  20. 20.

    f′⁢(x)=2x

  21. 21.

    f′⁢(t)=0

  22. 22.

    g′⁢(t)=18⁢t+6

  23. 23.

    g′⁢(x)=24⁢x2−120⁢x+150

  24. 24.

    f′⁢(x)=−3⁢x2+6⁢x−3

  25. 25.

    f′⁢(x)=18⁢x−12

  26. 26.

    h′⁢(x)=3⁢x2−2

  27. 27.

    f′⁢(x)=32⁢x−12⁢x⁢x

  28. 28.

    g′⁢(θ)=−sin⁡θ

  29. 29.
  30. 30.

    dd⁡x⁢(c)=limh→0c−ch=limh→00=0

  31. 31.

    a is f, b is f′, c is f′′

  32. 32.

    d is f, c is f′, b is f′′, and a is f′′′

  33. 33.

    f′⁢(x)=6⁢x5 f′′⁢(x)=30⁢x4 f′′′⁢(x)=120⁢x3 f(4)⁢(x)=360⁢x2

  34. 34.

    g′⁢(x)=−2⁢sin⁡x g′′⁢(x)=−2⁢cos⁡x g′′′⁢(x)=2⁢sin⁡x g(4)⁢(x)=2⁢cos⁡x

  35. 35.

    h′⁢(t)=2⁢t−et h′′⁢(t)=2−et h′′′⁢(t)=−et h(4)⁢(t)=−et

  36. 36.

    p′⁢(θ)=4⁢θ3−3⁢θ2 p′′⁢(θ)=12⁢θ2−6⁢θ p′′′⁢(θ)=24⁢θ−6 p(4)⁢(θ)=24

  37. 37.

    f′⁢(θ)=cos⁡θ+sin⁡θ f′′⁢(θ)=−sin⁡θ+cos⁡θ f′′′⁢(θ)=−cos⁡θ−sin⁡θ f(4)⁢(θ)=sin⁡θ−cos⁡θ

  38. 38.

    f′⁢(x)=f′′⁢(x)=f′′′⁢(x)=f(4)⁢(x)=0

  39. 39.

    • v⁢(t)=4⁢t3−8⁢t, a⁢(t)=12⁢t2−8

      a⁢(1.5)=19⁢ft/s2

      t=0 sec and t=2 sec

  40. 40.

    • v⁢(t)=5⁢ex−5, a⁢(t)=5⁢ex

      a⁢(2)=5⁢e2⁢ft/s2

      v⁢(t)=0 at t=0 sec, a⁢(0)=5⁢in/s2

  41. 41.

    Tangent line: y=2⁢(x−1)

  42. 42.

    Tangent line: y=t+4

  43. 43.

    Tangent line: y=x−1

  44. 44.

    Tangent line: y=4

  45. 45.

    Tangent line: y=2⁢(x−π4)−2

  46. 46.

    Tangent line: y=2⁢x+3

  47. 47.

    n=−3,2

  48. 48.

    The tangent line to f⁢(x)=ex at x=0 is y=x+1; thus e0.1≈y⁢(0.1)=1.1.

  49. 49.

    The tangent line to f⁢(x)=x4 at x=3 is y=108⁢(x−3)+81; thus (3.01)4≈y⁢(3.01)=108⁢(.01)+81=82.08.

Exercises B.4

  1. 1.

    F

  2. 2.

    F

  3. 3.

    T

  4. 4.

    Quotient Rule

  5. 5.

    F

  6. 6.

    Answers will vary.

  7. 7.

    dd⁡x⁢(cot⁡x) =dd⁡x⁢(cos⁡xsin⁡x)
    =sin⁡x⁢(−sin⁡x)−(cos⁡x)⁢(cos⁡x)(sin⁡x)2
    =−[(sin⁡x)2+(cos⁡x)2](sin⁡x)2
    =−1(sin⁡x)2=−csc2⁡x
  8. 8.

    dd⁡x⁢(csc⁡x) =dd⁡x⁢(1sin⁡x)
    =sin⁡x⋅0−1⋅(cos⁡x)(sin⁡x)2
    =−cos⁡x(sin⁡x)2=−csc⁡x⁢cot⁡x
  9. 9.

    • f′⁢(x)=(x2+3⁢x)+x⁢(2⁢x+3)

      f′⁢(x)=3⁢x2+6⁢x

      They are equal.

  10. 10.

    • g′⁢(x)=4⁢x⁢(5⁢x3)+2⁢x2⁢(15⁢x2)

      g′⁢(x)=50⁢x4

      They are equal.

  11. 11.

    • h′⁢(s)=2⁢(s+4)+(2⁢s−1)⁢(1)

      h′⁢(s)=4⁢s+7

      They are equal.

  12. 12.

    • f′⁢(x)=2⁢x⁢(3−x3)+(x2+5)⁢(−3⁢x2)

      f′⁢(x)=−5⁢x4−15⁢x2+6⁢x

      They are equal.

  13. 13.

    • f′⁢(x)=x⁢(2⁢x)−(x2+3)⁢1x2

      f′⁢(x)=1−3x2

      They are equal.

  14. 14.

    • g′⁢(x)=2⁢x2⁢(3⁢x2−4⁢x)−(x3−2⁢x2)⁢(4⁢x)4⁢x4

      g′⁢(x)=1/2

      They are equal.

  15. 15.

    • h′⁢(s)=4⁢s3⁢(0)−3⁢(12⁢s2)16⁢s6

      h′⁢(s)=−9/4⁢s−4

      They are equal.

  16. 16.

    • f′⁢(t)=(t+1)⁢(2⁢t)−(t2−1)⁢(1)(t+1)2

      f⁢(t)=t−1 when t≠−1, so f′⁢(t)=1.

      They are equal.

  17. 17.

    f′⁢(x)=sin⁡x+x⁢cos⁡x

  18. 18.

    f′⁢(t)=−2t3⁢(csc⁡t−4)+1t2⁢(−csc⁡t⁢cot⁡t)

  19. 19.

    H′⁢(y)=(y5−2⁢y3)⁢(14⁢y+1)+(5⁢y4−6⁢y2)⁢(7⁢y2+y−8)

  20. 20.

    F′⁢(y)=83⁢y5/3+15⁢y2/3=y23⁢(8⁢y+45)3

  21. 21.

    g′⁢(x)=−12(x−5)2

  22. 22.

    y′=4−x2⁢x⁢(x+4)2

  23. 23.

    g′⁢(x)=x+82⁢(x+4)2

  24. 24.

    g′⁢(t)=(cos⁡t−2⁢t2)⁢(5⁢t4)−(t5)⁢(−sin⁡t−4⁢t)(cos⁡t−2⁢t2)2

  25. 25.

    h′⁢(x)=−csc2⁡x−ex

  26. 26.

    h′⁢(t)=14⁢t+6

  27. 27.

    f′⁢(x)=(x+2)⁢(4⁢x3+6⁢x2)−(x4+2⁢x3)⁢(1)(x+2)2

  28. 28.

    f′⁢(x)=−1x2+52⁢x3⁢x=−2⁢x⁢x+52⁢x3⁢x

  29. 29.

    y′=−2⁢x−5−10x2=−2⁢x3+5⁢x2+10x2

  30. 30.

    g′⁢(x)=−1+2⁢x+3⁢x2(1+x+x2+x3)2

  31. 31.

    p′⁢(x)=−1x2−2x3−3x4=−x2+2⁢x+3x4

  32. 32.

    f′⁢(x)=7

  33. 33.

    f′⁢(t)=5⁢t4⁢(sec⁡t+et)+t5⁢(sec⁡t⁢tan⁡t+et)

  34. 34.

    f′⁢(x)=sin2⁡(x)+cos2⁡(x)+3⁢cos⁡(x)(cos⁡(x)+3)2

  35. 35.

    g′⁢(x)=0

  36. 36.

    g′⁢(t)=12⁢t2⁢et+4⁢t3⁢et−cos2⁡t+sin2⁡t

  37. 37.

    f′⁢(y)=y⁢(2⁢y3−5⁢y−1)⁢(12⁢y)+y⁢(6⁢y2−5)⁢(6⁢y2+7)+1⁢(2⁢y3−5⁢y−1)⁢(6⁢y2+7)=72⁢y5−64⁢y3−18⁢y2−70⁢y−7

  38. 38.

    F′⁢(x)=(8⁢x−1)⁢(x2+4⁢x+7)⁢(3⁢x2)+(8⁢x−1)⁢(2⁢x+4)⁢(x3−5)+(8)⁢(x2+4⁢x+7)⁢(x3−5)

  39. 39.

    h′⁢(x)=(t2⁢cos⁡t+2)⁢(2⁢t⁢sin⁡t+t2⁢cos⁡t)−(t2⁢sin⁡t+3)⁢(2⁢t⁢cos⁡t−t2⁢sin⁡t)(t2⁢cos⁡t+2)2

  40. 40.

    f′⁢(x)=2⁢x⁢ex⁢tan⁡x=x2⁢ex⁢tan⁡x+x2⁢ex⁢sec2⁡x

  41. 41.

    g′⁢(x)=2⁢sin⁡x⁢sec⁡x+2⁢x⁢cos⁡x⁢sec⁡x+2⁢x⁢sin⁡x⁢sec⁡x⁢tan⁡x=2⁢tan⁡x+2⁢x+2⁢x⁢tan2⁡x=2⁢tan⁡x+2⁢x⁢sec2⁡x

  42. 42.

    f′⁢(x)=1+ln⁡x

  43. 43.

    y=2⁢x+2

  44. 44.

    y=−(x−3⁢π2)−3⁢π2=−x

  45. 45.

    y=4

  46. 46.

    y=−9⁢x+1

  47. 47.

    x=3/2

  48. 48.

    x=0

  49. 49.

    f′⁢(x) is never 0.

  50. 50.

    x=−2,0

  51. 51.

    f′′⁢(x)=2⁢cos⁡x−x⁢sin⁡x

  52. 52.

    f(4)⁢(x)=−4⁢cos⁡x+x⁢sin⁡x

  53. 53.

    f′′⁢(x)=cot2⁡x⁢csc⁡x+csc3⁡x

  54. 54.

    f(8)=0

  55. 55.

    1

  56. 56.

    −3

  57. 57.

    −4

  58. 58.

    11

  59. 59.

    −125

  60. 60.

    14

  61. 61.
    • ()   −72  ()   118  ()   −92  ()   152

Exercises B.5

  1. 1.

    T

  2. 2.

    F

  3. 3.

    F

  4. 4.

    F

  5. 5.

    T

  6. 6.

    T

  7. 7.

    f′⁢(x)=10⁢(4⁢x3−x)9⋅(12⁢x2−1)=(120⁢x2−10)⁢(4⁢x3−x)9

  8. 8.

    f′⁢(t)=15⁢(3⁢t−2)4

  9. 9.

    g′⁢(θ)=3⁢(sin⁡θ+cos⁡θ)2⁢(cos⁡θ−sin⁡θ)

  10. 10.

    h′⁢(t)=(6⁢t+1)⁢e3⁢t2+t−1

  11. 11.

    f′⁢(x)=4⁢(x+1x)3⁢(1−1x2)

  12. 12.

    p′⁢(x)=12⁢(x2−1x2)5⁢(x+1x3)

  13. 13.

    f′⁢(x)=−3⁢sin⁡(3⁢x)

  14. 14.

    g′⁢(x)=5⁢sec2⁡(5⁢x)

  15. 15.

    h′⁢(x)=(2⁢θ+4)⁢sec2⁡(θ2+4⁢θ)

  16. 16.

    g′⁢(t)=(5⁢t4−1t2)⁢cos⁡(t5+1t)

  17. 17.

    h′⁢(t)=8⁢sin3⁡(2⁢t)⁢cos⁡(2⁢t)

  18. 18.

    p′⁢(t)=−3⁢cos2⁡(t2+3⁢t+1)⁢sin⁡(t2+3⁢t+1)⁢(2⁢t+3)

  19. 19.

    g′⁢(x)=2⁢(tan⁡x⁢sec2⁡x−x⁢sec2⁡(x2))

  20. 20.

    w′⁢(x)=3⁢x2⁢ex3⁢(sec⁡ex3)⁢(tan⁡ex3)

  21. 21.

    f′⁢(x)=−tan⁡x

  22. 22.

    f′⁢(x)=2/x

  23. 23.

    f′⁢(x)=2/x

  24. 24.

    g′⁢(t)=0

  25. 25.

    r′⁢(x)=−6⁢(x−1)x3⁢4⁢x−3

  26. 26.

    f′⁢(x)=12⁢x⁢(2⁢x3−1)⁢(3⁢x2−5)3⁢(x2+5⁢x−2)(2⁢x3−1)4

  27. 27.

    h′⁢(x)=200⁢(2⁢x+1)9⁢[(2⁢x+1)10+1]9

  28. 28.

    f′⁢(t)=−t4(2⁢t+1)⁢(t+1)

  29. 29.

    F′⁢(x)=2⁢(2⁢x+1)⁢(2⁢x+3)2⁢(24⁢x2+26⁢x+3)

  30. 30.

    f′⁢(x)=5⁢x2⁢cos⁡(5⁢x)+2⁢x⁢sin⁡(5⁢x)

  31. 31.

    f′⁢(x)=5⁢(x2+x)4⁢(2⁢x+1)⁢(3⁢x4+2⁢x)3+(x2+x)5⁢3⁢(3⁢x4+2⁢x)2⁢(12⁢x3+2)

  32. 32.

    g′⁢(t)=5⁢cos⁡(t2+3⁢t)⁢cos⁡(5⁢t−7)−(2⁢t+3)⁢sin⁡(t2+3⁢t)⁢sin⁡(5⁢t−7)

  33. 33.

    g′⁢(t)=10⁢t⁢cos⁡(1t)⁢e5⁢t2+1t2⁢sin⁡(1t)⁢e5⁢t2

  34. 34.

    f′⁢(x)=(5⁢x−9)3⁢4⁢cos⁡(4⁢x+1)−sin⁡(4⁢x+1)⁢15⁢(5⁢x−9)2(5⁢x−9)6

  35. 35.

    f′⁢(x)=tan⁡(5⁢x)⁢8⁢(4⁢x+1)−(4⁢x+1)2⁢5⁢sec2⁡(5⁢x)tan2⁡(5⁢x)

  36. 36.

    a′⁢(t)=7⁢t2⁢etan⁡(t2)⁢(2⁢t2⁢sec2⁡(t2)+3)

  37. 37.

    y′=−cos⁡x⁢sin⁡x⁢cos⁡(cos2⁡x)sin⁡(cos2⁡x)

  38. 38.

    k′⁢(x)=−sin⁡(x⁢sin⁡x3)⁢(3⁢x3⁢cos⁡x3+sin⁡x3)

  39. 39.

    f′⁢(x)=12⁢x−1/2−12⁢x−3/2=12⁢x−12⁢x3

  40. 40.

    f′⁢(x)=13⁢x−2/3+23⁢x−1/3=13⁢x23+23⁢x3

  41. 41.

    f′⁢(t)=−t1−t2

  42. 42.

    g′⁢(t)=t⁢cos⁡t+sin⁡t2⁢t

  43. 43.

    h′⁢(x)=1.5⁢x0.5=1.5⁢x

  44. 44.

    f′⁢(x)=π⁢xπ−1+1.9⁢x0.9

  45. 45.

    g′⁢(x)=x⁢(1)−(x+7)⁢(1/2⁢x−1/2)x=12⁢x−72⁢x3

  46. 46.

    f′⁢(t)=15⁢x−4/5⁢(sec⁡t+et)+t5⁢(sec⁡t⁢tan⁡t+et)

  47. 47.

    15

  48. 48.

    90

  49. 49.
    • ()   6  ()   1  ()   −3  ()   1.5

  50. 50.
    • ()   12  ()   2.5  ()   9  ()   35

  51. 51.

    y=0

  52. 52.

    y=15⁢(t−1)+1

  53. 53.

    y=−3⁢(θ−π/2)+1

  54. 54.

    y=−5⁢e⁢(t+1)+e

  55. 55.

    In both cases the derivative is the same: 1/x.

  56. 56.

    In both cases the derivative is the same: k/x.

  57. 57.

    Let g⁢(x)=−x. Then

    • f∘g=f, so f′⁢(−x)=f′∘g⁢(x)=−f′∘g⁢(x)⁢g′⁢(x)=−(f∘g)′⁢(x)=−f′⁢(x)

      f∘g=−f, so f′⁢(−x)=f′∘g⁢(x)=−f′∘g⁢(x)⁢g′⁢(x)=−(f∘g)′⁢(x)=f′⁢(x)

  58. 58.

    Let h⁢(x)=x−1. Then dd⁡x⁢f⁢(x)g⁢(x)=dd⁡x⁢[f⁢(x)⋅h⁢(g⁢(x))]=dd⁡x⁢[f⁢(x)]⋅h⁢(g⁢(x))+f⁢(x)⋅dd⁡x⁢[h⁢(g⁢(x))]=f′⁢(x)⋅h⁢(g⁢(x))+f⁢(x)⋅h′⁢(g⁢(x))⋅g′⁢(x)=f′⁢(x)⁢[g⁢(x)]−1−f⁢(x)⁢[g⁢(x)]−2⁢g′⁢(x)=f′⁢(x)⁢g⁢(x)−f⁢(x)⁢g′⁢(x)[g⁢(x)]2

  59. 59.

    [f⁢(g⁢(x))]′′=[f′⁢(g⁢(x))⁢g′⁢(x)]′=[f′⁢(g⁢(x))]′⁢g′⁢(x)+f′⁢(g⁢(x))⁢g′′⁢(x)=f′′⁢(g⁢(x))⁢g′⁢(x)⁢g′⁢(x)+f′⁢(g⁢(x))⁢g′′⁢(x)=f′′⁢(g⁢(x))⁢[g′⁢(x)]2+f′⁢(g⁢(x))⁢g′′⁢(x)

  60. 60.

    • ∘F/mph

      The sign would be negative; when the wind is blowing at 10 mph, any increase in wind speed will make it feel colder, i.e., a lower number on the Fahrenheit scale.

  61. 61.

    2⁢x⁢ex⁢cot⁡x+x2⁢ex⁢cot⁡x−x2⁢ex⁢csc2⁡x

Exercises B.6

  1. 1.

    Answers will vary.

  2. 2.

    The Chain Rule.

  3. 3.

    T

  4. 4.

    T

  5. 5.

    d⁡yd⁡x=−4⁢x32⁢y+1

  6. 6.

    d⁡yd⁡x=−y3/5x3/5

  7. 7.

    d⁡yd⁡x=sin⁡x⁢sec⁡y

  8. 8.

    d⁡yd⁡x=yx

  9. 9.

    d⁡yd⁡x=yx

  10. 10.

    −ex⁢x⁢(x+2)⁢e−y

  11. 11.

    −2⁢sin⁡(y)⁢cos⁡(y)x

  12. 12.

    −xy2

  13. 13.

    12⁢y+2

  14. 14.

    x2+2⁢x⁢y2−y2⁢x2⁢y−x+y2

  15. 15.

    −cos⁡(x)⁢(x+cos⁡(y))+sin⁡(x)+ysin⁡(y)⁢(sin⁡(x)+y)+x+cos⁡(y)

  16. 16.

    −xy

  17. 17.

    −2⁢x+y2⁢y+x

  18. 18.

    ex⁢(x+1)ey⁢(y+1)

  19. 19.

    3⁢x2⁢y⁢cos⁡(x3)−sin⁡(y3)3⁢x⁢y2⁢cos⁡(y3)−sin⁡(x3)

  20. 20.

    y−4⁢x⁢y⁢x⁢y2⁢x2⁢x⁢y−x

  21. 21.

    d⁡yd⁡x=y⁢(y−2⁢x)x⁢(x−2⁢y)

  22. 22.

    d⁡yd⁡x=−y+2⁢x2⁢y+x

  23. 23.

    • y=0

      y=−1.859⁢(x−0.1)+0.281

  24. 24.

    • x=1

      y=−3⁢38⁢(x−.6)+.8≈−0.65⁢(x−0.775)+0.894

      y=1

  25. 25.

    • y=4

      y=0.93⁢(x−2)−1084

  26. 26.

    • y=−1/3⁢x+1

      y=3⁢3/4

  27. 27.

    • y=−13⁢(x−72)+6+3⁢32

      y=3⁢(x−4+3⁢32)+32

  28. 28.

    • y=−3⁢x4−32

      y=72⁢x−32

  29. 29.

    d2⁡yd⁡x2=(2⁢y+1)⁢(−12⁢x2)+4⁢x3⁢(2⁢−4⁢x32⁢y+1)(2⁢y+1)2

  30. 30.

    d2⁡yd⁡x2=35⁢y3/5x8/5+35⁢1y⁢x6/5

  31. 31.

    d2⁡yd⁡x2=cos⁡x⁢cos⁡y+sin2⁡x⁢tan⁡ycos2⁡y

  32. 32.

    d2⁡yd⁡x2=0

  33. 33.

    In each, d⁡yd⁡x=−yx.

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