Chapter H

Exercises H.1

  1. 1.

    T

  2. 2.

    F

  3. 3.

    sin⁡x−x⁢cos⁡x+C

  4. 4.

    −e−x−x⁢e−x+C

  5. 5.

    −x2⁢cos⁡x+2⁢x⁢sin⁡x+2⁢cos⁡x+C

  6. 6.

    −x3⁢cos⁡x+3⁢x2⁢sin⁡x+6⁢x⁢cos⁡x−6⁢sin⁡x+C

  7. 7.

    1/2⁢ex2+C

  8. 8.

    x3⁢ex−3⁢x2⁢ex+6⁢x⁢ex−6⁢ex+C

  9. 9.

    −12⁢x⁢e−2⁢x−e−2⁢x4+C

  10. 10.

    12⁢ex⁢(sin⁡x−cos⁡x)+C

  11. 11.

    1/5⁢e2⁢x⁢(sin⁡x+2⁢cos⁡x)+C

  12. 12.

    113⁢e2⁢x⁢(2⁢sin⁡(3⁢x)−3⁢cos⁡(3⁢x))+C

  13. 13.

    110⁢e5⁢x⁢(sin⁡(5⁢x)+cos⁡(5⁢x))+C

  14. 14.

    −12⁢cos2⁡x+C

  15. 15.

    1−x2+x⁢sin−1⁡(x)+C

  16. 16.

    x⁢tan−1⁡(2⁢x)−14⁢ln⁡|4⁢x2+1|+C

  17. 17.

    12⁢x2⁢tan−1⁡(x)−x2+12⁢tan−1⁡(x)+C

  18. 18.

    x⁢cos−1⁡x−1−x2+C

  19. 19.

    12⁢x2⁢ln⁡|x|−x24+C

  20. 20.

    −x24+12⁢x2⁢ln⁡|x|−2⁢x⁢ln⁡|x|+2⁢x+C

  21. 21.

    −x24+12⁢x2⁢ln⁡|x−1|−x2−12⁢ln⁡|x−1|+C

  22. 22.

    12⁢x2⁢ln⁡(x2)−x22+C

  23. 23.

    13⁢x3⁢ln⁡|x|−x39+C

  24. 24.

    2⁢x+x⁢(ln⁡|x|)2−2⁢x⁢ln⁡|x|+C

  25. 25.

    2⁢x+x⁢(ln⁡|x+1|)2+(ln⁡|x+1|)2−2⁢x⁢ln⁡|x+1|−2⁢ln⁡|x+1|+2+C

  26. 26.

    x⁢tan⁡x+ln⁡|cos⁡x|+C

  27. 27.

    ln⁡|sin⁡x|−x⁢cot⁡x+C

  28. 28.

    25⁢(x−2)5/2+43⁢(x−2)3/2+C

  29. 29.

    13⁢(x2−2)3/2+C

  30. 30.

    sec⁡x+C

  31. 31.

    x⁢sec⁡x−ln⁡|sec⁡x+tan⁡x|+C

  32. 32.

    −x⁢csc⁡x−ln⁡|csc⁡x+cot⁡x|+C

  33. 33.

    x⁢sinh⁡x−cosh⁡x+C

  34. 34.

    x⁢cosh⁡x−sinh⁡x+C

  35. 35.

    x⁢sinh−1⁡x−x2+1+C

  36. 36.

    x⁢tanh−1⁡x+12⁢ln⁡|x2−1|+C

  37. 37.

    1/2⁢x⁢(sin⁡(ln⁡x)−cos⁡(ln⁡x))+C

  38. 38.

    2⁢sin⁡(x)−2⁢x⁢cos⁡(x)+C

  39. 39.

    12⁢x⁢ln⁡|x|−x2+C

  40. 40.

    2⁢x⁢ex−2⁢ex+C

  41. 41.

    1/2⁢x2+C

  42. 42.

    12⁢ex2⁢(x2−1)+C

  43. 43.

    π

  44. 44.

    −2/e

  45. 45.

    0

  46. 46.

    3⁢π22−12

  47. 47.

    1/2

  48. 48.

    6−2⁢e

  49. 49.

    34⁢e2−54⁢e4

  50. 50.

    12+eπ2

  51. 51.

    15⁢(eπ+e−π)

  52. 52.

    313⁢(1+e2⁢π/3)+C

  53. 53.
  54. 54.

    • π⁢(e−2)

      π2⁢(e2+1)

  55. 55.

    • bn=(−1)n+1⁢2/n

      answers will vary

  56. 56.

    • bn=(−1)(n−1)/2⁢4/π⁢n2 for odd n and bn=0 for even n

      answers will vary

Exercises H.2

  1. 1.

    F

  2. 2.

    F

  3. 3.

    F

  4. 4.

    F

  5. 5.

    14⁢sin4⁡x+C

  6. 6.

    12⁢x+14⁢sin⁡2⁢x+C

  7. 7.

    38⁢x+14⁢sin⁡2⁢x+132⁢sin⁡4⁢x+C

  8. 8.

    15⁢cos5⁡x−13⁢cos3⁡x+C

  9. 9.

    16⁢cos6⁡x−14⁢cos4⁡x+C

  10. 10.

    111⁢sin11⁡x−29⁢sin9⁡x+17⁢sin7⁡x+C

  11. 11.

    12⁢cos2⁡x−ln⁡|cos⁡x|+C

  12. 12.

    x8−132⁢sin⁡(4⁢x)+C

  13. 13.

    (27⁢cos3⁡x−23⁢cos⁡x)⁢cos⁡x+C

  14. 14.

    12⁢(−13⁢cos⁡(3⁢x)+cos⁡(−x))+C

  15. 15.

    12⁢(14⁢sin⁡(4⁢x)−110⁢sin⁡(10⁢x))+C

  16. 16.

    12⁢(1π⁢sin⁡(π⁢x)−13⁢π⁢sin⁡(3⁢π⁢x))+C

  17. 17.

    12⁢(sin⁡(x)+13⁢sin⁡(3⁢x))+C

  18. 18.

    1π⁢sin⁡(π2⁢x)+13⁢π⁢sin⁡(π⁢x)+C

  19. 19.

    tan⁡x−x+C

  20. 20.

    15⁢tan5⁡x+13⁢tan3⁡x+C

  21. 21.

    tan6⁡(x)6+tan4⁡x4+C

  22. 22.

    tan4⁡(x)4+C

  23. 23.

    sec5⁡(x)5−sec3⁡x3+C

  24. 24.

    sec9⁡(x)9−2⁢sec7⁡x7+sec5⁡x5+C

  25. 25.

    13⁢tan3⁡x−tan⁡x+x+C

  26. 26.

    14⁢tan⁡x⁢sec3⁡x+38⁢(sec⁡x⁢tan⁡x+ln⁡|sec⁡x+tan⁡x|)+C

  27. 27.

    12⁢(sec⁡x⁢tan⁡x−ln⁡|sec⁡x+tan⁡x|)+C

  28. 28.

    14⁢tan⁡x⁢sec3⁡x−18⁢(sec⁡x⁢tan⁡x+ln⁡|sec⁡x+tan⁡x|)+C

  29. 29.

    ln⁡|csc⁡x−cot⁡x|+C

  30. 30.

    13⁢csc3⁡x−15⁢csc5⁡x+C

  31. 31.

    −12⁢cot2⁡x+ln⁡|csc⁡x|+C

  32. 32.

    −19⁢cot9⁡x−17⁢cot7⁡x+C

  33. 33.

    25

  34. 34.

    0

  35. 35.

    32/315

  36. 36.

    1/2

  37. 37.

    2/3

  38. 38.

    1/5

  39. 39.

    16/15

  40. 40.

    3−π3

  41. 41.

    1

Exercises H.3

  1. 1.

    backwards

  2. 2.

    5⁢sin⁡θ

  3. 3.

    • tan2⁡θ+1=sec2⁡θ

      9⁢sec2⁡θ.

  4. 4.

    Because we are considering a>0 and x=a⁢sin⁡θ, which means θ=sin−1⁡(x/a). The arcsine function has a domain of −π/2≤θ≤π/2; on this domain, cos⁡θ≥0, so a⁢cos⁡θ is always non-negative, allowing us to drop the absolute value signs.

  5. 5.

    12⁢(x⁢x2+1+ln⁡|x2+1+x|)+C

  6. 6.

    12⁢x⁢x2−1−12⁢ln⁡|x+x2−1|+C

  7. 7.

    x⁢x2+1/4+14⁢ln⁡|2⁢x2+1/4+2⁢x|+C=12⁢x⁢4⁢x2+1+14⁢ln⁡|4⁢x2+1+2⁢x|+C

  8. 8.

    16⁢sin−1⁡(3⁢x)+32⁢1/9−x2+C=16⁢sin−1⁡(3⁢x)+12⁢1−9⁢x2+C

  9. 9.

    4⁢(12⁢x⁢x2−1/16−132⁢ln⁡|4⁢x+4⁢x2−1/16|)+C=12⁢x⁢16⁢x2−1−18⁢ln⁡|4⁢x+16⁢x2−1|+C

  10. 10.

    8⁢ln⁡|x2+22+x2|+C; with Section 7.4, we can state the answer as 8⁢sinh−1⁡(x/2)+C.

  11. 11.

    3⁢sin−1⁡(x7)+C (Trig. Subst. is not needed)

  12. 12.

    5⁢ln⁡|x8+x2−88|+C

  13. 13.

    2⁢(x4⁢x2+4+ln⁡|x2+12+x2|)+C

  14. 14.

    12⁢(sin−1⁡x+x⁢1−x2)+C

  15. 15.

    12⁢(9⁢sin−1⁡(x/3)+x⁢9−x2)+C

  16. 16.

    12⁢x⁢x2−16−8⁢ln⁡|x4+x2−164|+C

  17. 17.

    7⁢tan−1⁡(x7)+C

  18. 18.

    3⁢sin−1⁡(x3)+C

  19. 19.

    14⁢sin−1⁡(x5)+C

  20. 20.

    23⁢sec−1⁡(|x|/3)+C

  21. 21.

    54⁢sec−1⁡(|x|/4)+C

  22. 22.

    12⁢sin−1⁡(x2)+C

  23. 23.

    tan−1⁡(x−17)7+C

  24. 24.

    2⁢sin−1⁡(x−34)+C

  25. 25.

    3⁢sin−1⁡(x−45)+C

  26. 26.

    tan−1⁡(x+35)+C

  27. 27.

    x2−11−11⁢sec−1⁡(x/11)+C

  28. 28.

    x2−3+C (Trig. Subst. is not needed)

  29. 29.

    −1x2+9+C   (Trig. Subst. is not needed)

  30. 30.

    52⁢x⁢x2−10+25⁢ln⁡|x10+x2−1010|+C

  31. 31.

    118⁢x+2x2+4⁢x+13+154⁢tan−1⁡(x+23)+C

  32. 32.

    x1−x2−sin−1⁡x+C

  33. 33.

    17⁢(−5−x2x−sin−1⁡(x/5))+C

  34. 34.

    12⁢x⁢x2+3−32⁢ln⁡|x2+33+x3|+C

  35. 35.

    π/2

  36. 36.

    16⁢3−8⁢ln⁡(2+3)

  37. 37.

    2⁢2+2⁢ln⁡(1+2)

  38. 38.

    π/4+1/2)

  39. 39.

    9⁢sin−1⁡(1/3)+2⁢2   Note: the new bounds of integration are sin−1⁡(−1/3)<θ<sin−1⁡(1/3). The final answer comes with recognizing that sin−1⁡(−1/3)=−sin−1⁡(1/3) and that cos⁡(sin−1⁡(1/3))=cos⁡(sin−1⁡(−1/3))=2⁢2/3.

  40. 40.

    π/8

  41. 41.

    • π⁢(1−π4)

      π⁢(2−ln⁡(1+2))

Exercises H.4

  1. 1.

    rational

  2. 2.

    T

  3. 3.

    Ax+Bx−3

  4. 4.

    Ax−3+Bx+3

  5. 5.

    Ax−7+Bx+7

  6. 6.

    Ax+B⁢x+Cx2+7

  7. 7.

    3⁢ln⁡|x−2|+4⁢ln⁡|x+5|+C

  8. 8.

    9⁢ln⁡|x+1|−2⁢ln⁡|x|+C

  9. 9.

    13⁢(ln⁡|x+2|−ln⁡|x−2|)+C

  10. 10.

    ln⁡|x+5|−2x+5+C

  11. 11.

    −4x+8−3⁢ln⁡|x+8|+C

  12. 12.

    5x+1+7⁢ln⁡|x|+2⁢ln⁡|x+1|+C

  13. 13.

    −ln⁡|2⁢x−3|+5⁢ln⁡|x−1|+2⁢ln⁡|x+3|+C

  14. 14.

    −15⁢ln⁡|5⁢x−1|+23⁢ln⁡|3⁢x−1|+37⁢ln⁡|7⁢x+3|+C

  15. 15.

    x+ln⁡|x−1|−ln⁡|x+2|+C

  16. 16.

    x22+x+1259⁢ln⁡|x−5|+649⁢ln⁡|x+4|+C

  17. 17.

    2⁢x+C

  18. 18.

    16⁢(−ln⁡|x2+2⁢x+3|+2⁢ln⁡|x|−2⁢tan−1⁡(x+12))+C

  19. 19.

    1x+12⁢ln⁡|x−1x+1|+C

  20. 20.

    −32⁢ln⁡|x2+4⁢x+10|+x+tan−1⁡(x+26)6+C

  21. 21.

    ln⁡|3⁢x2+5⁢x−1|+2⁢ln⁡|x+1|+C

  22. 22.

    2⁢ln⁡|x−3|+2⁢ln⁡|x2+6⁢x+10|−4⁢tan−1⁡(x+3)+C

  23. 23.

    ln⁡|x|−12⁢ln⁡(x2+1)−tan−1⁡x−12⁢(x2+1)+C

  24. 24.

    910⁢ln⁡|x2+9|+15⁢ln⁡|x+1|−415⁢tan−1⁡(x3)+C

  25. 25.

    12⁢(3⁢ln⁡|x2+2⁢x+17|−4⁢ln⁡|x−7|+tan−1⁡(x+14))+C

  26. 26.

    12⁢ln⁡(x2+1)−12⁢tan−1⁡(x2)+C

  27. 27.

    −14⁢ln⁡(x2+3)+14⁢ln⁡(x2+1)+C=14⁢ln⁡x2+1x2+3+C

  28. 28.

    −12⁢(x2+2⁢x+4)−2⁢39⁢tan−1⁡(x+13)−2⁢(x+1)3⁢(x2+2⁢x+4)+C

  29. 29.

    3⁢(ln⁡|x2−2⁢x+11|+ln⁡|x−9|)+3⁢25⁢tan−1⁡(x−110)+C

  30. 30.

    12⁢ln⁡|x2+10⁢x+27|+5⁢ln⁡|x+2|−6⁢2⁢tan−1⁡(x+52)+C

  31. 31.

    132⁢ln⁡|x−2|−132⁢ln⁡|x+2|−116⁢tan−1⁡(x/2)+C

  32. 32.

    ln⁡x−ln⁡|x+1|+C

  33. 33.

    ln⁡x−12⁢ln⁡(x2+1)+12⁢1x2+1+C

  34. 34.

    tan−1⁡x−xx2+1+C

  35. 35.

    ln⁡(2000/243)≈2.108

  36. 36.

    5⁢ln⁡(9/4)−13⁢ln⁡(17/2)≈3.3413

  37. 37.

    −π/4+tan−1⁡3−ln⁡(11/9)≈0.263

  38. 38.

    1/8

  39. 39.

Exercises H.5

  1. 1.

    x⁢sin−1⁡x+1−x2+C

  2. 2.

    16⁢sin3⁡2⁢x−110⁢sin5⁡2⁢x+C

  3. 3.

    18⁢ln⁡|x−2|−9⁢ln⁡|x−1|−5⁢ln⁡|x−3|+C

  4. 4.

    15⁢sec5⁡x+C

  5. 5.

    x25⁢x2+25+C

  6. 6.

    2⁢ln⁡|2−4−x2x|+4−x2+C

  7. 7.

    2⁢ln⁡|x−1|−ln⁡|x|−1x−1−1(x−1)2+C

  8. 8.

    −4+4⁢x−x2+2⁢sin−1⁡(x−28)+C

  9. 9.

    12⁢ex2⁢(x2−1)+C

  10. 10.

    3x+83+ln[x+83−2]2−ln|(x+8)23+2x+83+4|−63tan−1x+83+13+C

  11. 11.

    113⁢e2⁢x⁢(2⁢sin⁡3⁢x−3⁢cos⁡3⁢x)+C

  12. 12.

    14⁢sin4⁡x−16⁢sin6⁡x+C

  13. 13.

    −4−x2+C

  14. 14.

    13⁢x3−x2+3⁢x−12⁢x−14⁢ln⁡|x|−234⁢ln⁡|x+2|+C

  15. 15.

    2⁢tan−1⁡x+C

  16. 16.

    ln⁡|sec⁡ex+tan⁡ex|+C

  17. 17.

    127⁢[6⁢x⁢sin⁡3⁢x−(9⁢x2−2)⁢cos⁡3⁢x]+C

  18. 18.

    27⁢cos7/2⁡x−23⁢cos3/2⁡x+C

  19. 19.

    23⁢(1+ex)3/2+C

  20. 20.

    116[2x4⁢x2+9−9ln(2x+4⁢x2+9]+C

  21. 21.

    13⁢tan3⁡x+C

  22. 22.

    −x⁢csc⁡x+ln⁡|csc⁡x−cot⁡x|+C

  23. 23.

    −14⁢(8−x3)4/3+C

  24. 24.

    2⁢sin⁡x−2⁢x⁢cos⁡x+C

  25. 25.

    110⁢(3−2⁢x)5/2−12⁢(3−2⁢x)3/2+C

  26. 26.

    12⁢e2⁢x−ex+ln⁡(1+ex)+C

  27. 27.

    25⁢x5/2−83⁢x3/2+6⁢x1/2+C

  28. 28.

    13⁢(16−x2)3/2−16⁢(16−x2)1/2+C

  29. 29.

    112⁢ln⁡|x+5|−152⁢ln⁡|x+7|+C

  30. 30.

    x⁢tan−1⁡5⁢x−110⁢ln⁡(1+25⁢x2)+C

  31. 31.

    etan⁡x+C

  32. 32.

    15⁢ln⁡|5⁢x+7+5⁢x2|+C

  33. 33.

    −15⁢cot5⁡x+13⁢cot3⁡x−cot⁡x−x+C

  34. 34.

    15⁢(x2−25)5/2+253⁢(x2−25)3/2+C

  35. 35.

    13⁢x3−14⁢tanh⁡4⁢x+C

  36. 36.

    −14⁢x2⁢e−4⁢x−18⁢x⁢e−4⁢x−132⁢e−4⁢x+C

  37. 37.

    3⁢sin−1⁡(x+56)+C

  38. 38.

    ln⁡(x+3)2⁢(x2+9)2|x−3|5+13⁢tan−1⁡x3+C

  39. 39.

    13⁢sec3⁡x−sec⁡x+C

  40. 40.

    x3⁢sin⁡x+3⁢x2⁢cos⁡x−6⁢x⁢sin⁡x−6⁢cos⁡x+sin⁡x+C

  41. 41.

    −2⁢sin−1⁡(2⁢x3)−1x⁢9−4⁢x2+C

  42. 42.

    24⁢x−103⁢ln⁡|sin⁡3⁢x|−13⁢cot⁡3⁢x+C

  43. 43.

    −ln⁡x+4x4+4⁢ln⁡|1−x4|+C

  44. 44.

    −2⁢1+cos⁡x+C

  45. 45.

    −x2⁢(25+x2)+110⁢tan−1⁡(x5)+C

  46. 46.

    ln⁡(x2+4)−32⁢tan−1⁡x2+75⁢tan−1⁡x5+C

  47. 47.

    14⁢x4−2⁢x2+4⁢ln⁡|x|+C

  48. 48.

    25⁢x5/2⁢ln⁡x−425⁢x5/2+C

  49. 49.

    364⁢(2⁢x+3)8/3−920⁢(2⁢x+3)5/3+2716⁢(2⁢x+3)2/3+C

  50. 50.

    exx+1+C

  51. 51.

    −17⁢cos⁡7⁢x+C

  52. 52.

    x22⁢sin−1⁡x−14⁢sin−1⁡x+x4⁢1−x2+C

  53. 53.
  54. 54.

    ln⁡|1+tan⁡θ2|−ln⁡|1−tan⁡θ2|+C

  55. 55.

    12⁢ln⁡|tan⁡θ2|−14⁢tan2⁡θ2+C.

Exercises H.6

  1. 1.

    The interval of integration is finite, and the integrand is continuous on that interval.

  2. 2.

    converge

  3. 3.

    converges; could also state ≤10.

  4. 4.

    p>1

  5. 5.

    p>1

  6. 6.

    p<1

  7. 7.

    e5/2

  8. 8.

    1/2

  9. 9.

    1/3

  10. 10.

    π/3

  11. 11.

    1/ln⁡2

  12. 12.

    diverges

  13. 13.

    diverges

  14. 14.

    diverges

  15. 15.

    1

  16. 16.

    diverges

  17. 17.

    diverges

  18. 18.

    diverges

  19. 19.

    diverges

  20. 20.

    diverges

  21. 21.

    2⁢3

  22. 22.

    6

  23. 23.

    diverges

  24. 24.

    diverges

  25. 25.

    diverges

  26. 26.

    2+2⁢2

  27. 27.

    1

  28. 28.

    1/2

  29. 29.

    0

  30. 30.

    π/2

  31. 31.

    −1/4

  32. 32.

    diverges

  33. 33.

    −1

  34. 34.

    1

  35. 35.

    diverges

  36. 36.

    1/2

  37. 37.

    diverges; Limit Comparison Test with 1/x.

  38. 38.

    converges; Limit Comparison Test with 1/x3/2.

  39. 39.

    diverges; Limit Comparison Test with 1/x.

  40. 40.

    converges; Direct Comparison Test with x⁢e−x.

  41. 41.

    converges; Direct Comparison Test with e−x.

  42. 42.

    converges; Direct Comparison Test with x⁢e−x.

  43. 43.

    converges; Direct Comparison Test with 1/(x2−1).

  44. 44.

    diverges; Direct Comparison Test with x/(x2+1).

  45. 45.

    converges; Direct Comparison Test with 1/ex.

  46. 46.

    converges; Limit Comparison Test with 1/ex.

  47. 47.

    • e−λ⁢a

      1λ

      e−1

  48. 48.

Exercises H.7

  1. 1.

    F

  2. 2.

    When the antiderivative cannot be computed and when the integrand is unknown.

  3. 3.

    They are superseded by the Trapezoidal Rule; it takes an equal amount of work and is generally more accurate.

  4. 4.

    It is superseded by the Trapezoidal Rule; it is about as accurate, but takes more work.

  5. 5.

    • 3/4

      2/3

      2/3

  6. 6.

    • 250

      250

      250

  7. 7.

    • 14⁢(1+2)⁢π≈1.896

      16⁢(1+2⁢2)⁢π≈2.005

      2

  8. 8.

    • 2+2+3≈5.15

      2/3⁢(3+2+2⁢3)≈5.25

      16/3≈5.33

  9. 9.

    • 38.5781

      147/4≈36.75

      147/4≈36.75

  10. 10.

    • 0.2207

      0.2005

      1/5

  11. 11.

    • 0

      0

      0

  12. 12.

    • 9⁢(1+3)/2≈12.294

      3+6⁢3≈13.392

      9⁢π/2≈14.137

  13. 13.

    Trapezoidal Rule: 0.9006

    Simpson’s Rule: 0.90452

  14. 14.

    Trapezoidal Rule: 3.0241

    Simpson’s Rule: 2.9315

  15. 15.

    Trapezoidal Rule: 13.9604

    Simpson’s Rule: 13.9066

  16. 16.

    Trapezoidal Rule: 3.0695

    Simpson’s Rule: 3.14295

  17. 17.

    Trapezoidal Rule: 1.1703

    Simpson’s Rule: 1.1873

  18. 18.

    Trapezoidal Rule: 2.52971

    Simpson’s Rule: 2.5447

  19. 19.

    Trapezoidal Rule: 1.0803

    Simpson’s Rule: 1.077

  20. 20.

    Trapezoidal Rule: 3.5472

    Simpson’s Rule: 3.6133

  21. 21.

    • n=161 (using max⁡(f′′⁢(x))=1)

      n=12 (using max⁡(f(4)⁢(x))=1)

  22. 22.

    • n=150 (using max⁡(f′′⁢(x))=1)

      n=18 (using max⁡(f(4)⁢(x))=7)

  23. 23.

    • n=1004 (using max⁡(f′′⁢(x))=39)

      n=62 (using max⁡(f(4)⁢(x))=800)

  24. 24.

    • n=5591 (using max⁡(f′′⁢(x))=300)

      n=46 (using max⁡(f(4)⁢(x))=24)

  25. 25.

    • Area is 30.8667 cm2.

      Area is 308,667 yd2.

  26. 26.

    • Area is 25.0667 cm2

      Area is 250,667 yd2

  27. 27.

    Let f⁢(x)=a⁢(x−x1)2+b⁢(x−x1)+c, so that f⁢(x1)=c=y1, f⁢(x1+Δ⁢x)=a⁢Δ⁢x2+b⁢Δ⁢x+c=y2, and f⁢(x1+2⁢Δ⁢x)=4⁢a⁢Δ⁢x2+2⁢b⁢Δ⁢x+c=y3. Therefore, a=y1−2⁢y2+y32⁢(Δ⁢x)2 and b=4⁢y2−y3−3⁢y12⁢Δ⁢x, and ∫x1x1+2⁢Δ⁢xa⁢(x−x1)2+b⁢(x−x1)+c⁢d⁡x=a⁢(2⁢Δ⁢x)33+b⁢(2⁢Δ⁢x)22+c⁢(2⁢Δ⁢x)=4⁢(y1−2⁢y2+y3)⁢Δ⁢x3+(4⁢y2−y3−3⁢y1)⁢Δ⁢x+2⁢y1⁢Δ⁢x=Δ⁢x3⁢(4⁢y1−8⁢y2+4⁢y3+12⁢y2−3⁢y3−9⁢y1+6⁢y1)=Δ⁢x3⁢(y1+4⁢y2+y3).

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